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Acetic acid reacts with sodium metal at room temperature to produce

In the reaction $C_8H_6O_4$ $\xrightarrow{\Delta} X$ $\xrightarrow{NH_3}$,the compound $X$ is

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What happens when $LiAlH_4$ is added to an ester?

Arrange the following compounds in decreasing order of reactivity for the hydrolysis reaction:
$(I) C_6H_5COCl$
$(II) NO_2-C_6H_4-COCl$
$(III) CH_3-C_6H_4-COCl$
$(IV) OHC-C_6H_4-COCl$

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Give the reactions of benzoic acid $(C_6H_5COOH)$ with the following:
$(i)$ Sodium metal
$(ii)$ Solution of sodium hydroxide $(NaOH)$
$(iii)$ Solution of sodium bicarbonate $(NaHCO_3)$
$(iv)$ $P_2O_5$ or conc. $H_2SO_4$ $+$ heat
$(v)$ $PCl_5$
$(vi)$ $PCl_3$
$(vii)$ $SOCl_2$
$(viii)$ $NH_3$ $+$ high temperature
$(ix)$ $LiAlH_4$ / ether or $B_2H_6$
$(x)$ Sodalime $(NaOH + CaO)$ $+$ heat
$(xi)$ Conc. $HNO_3$ $+$ conc. $H_2SO_4$ $+$ heat
$(xii)$ $Br_2 + FeBr_3$
$(xiii)$ Oleum $(H_2SO_4 + SO_3)$ $+$ heat

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