In the shown AC circuit,the phase difference | vedclass

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(C) In the upper branch containing the capacitor,the current $I_1$ leads the applied voltage $V$ by a phase angle of $\phi_1 = \frac{\pi}{2}$.In the l

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$\frac{\pi}{2} + 	an^{-1} \left( \frac{X_L}{R} ight)$

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(C) In the upper branch containing the capacitor,the current $I_1$ leads the applied voltage $V$ by a phase angle of $\phi_1 = \frac{\pi}{2}$.In the lower branch containing the resistor $R$ and inductor $X_L$,the current $I_2$ lags behind the applied voltage $V$ by a phase angle $\phi_2 = 	an^{-1} \left( \frac{X_L}{R} ight)$.The total phase difference between the two currents $I_1$ and $I_2$ is the sum of their individual phase shifts relative to the voltage $V$.Therefore,the phase difference $\Delta \phi = \phi_1 + \phi_2 = \frac{\pi}{2} + 	an^{-1} \left( \frac{X_L}{R} ight)$.

In the shown $AC$ circuit,the phase difference between currents $I_1$ and $I_2$ is:

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