In the spinel structure,oxide ions are cubica | vedclass

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Question

(B) In a cubic-closest packed $(CCP)$ structure,the number of oxide ions $(O^{2-})$ per unit cell is $4$.The number of tetrahedral voids is $2 	imes

Vedclass · Accepted Answer

$AB_2O_4$

Vedclass · Answer

(B) In a cubic-closest packed $(CCP)$ structure,the number of oxide ions $(O^{2-})$ per unit cell is $4$.The number of tetrahedral voids is $2 	imes 4 = 8$.The number of octahedral voids is $4$.Given that $1/8$ of tetrahedral voids are occupied by $A^{2+}$ cations:Number of $A^{2+} = 8 	imes (1/8) = 1$.Given that $1/2$ of octahedral voids are occupied by $B^{3+}$ cations:Number of $B^{3+} = 4 	imes (1/2) = 2$.Therefore,the ratio of $A : B : O$ is $1 : 2 : 4$.The general formula is $AB_{2}O_{4}$.

In the spinel structure,oxide ions are cubical-closest packed where $1/8$ of tetrahedral voids are occupied by $A^{2+}$ cations and $1/2$ of octahedral voids are occupied by $B^{3+}$ cations. The general formula of the compound having spinel structure is

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