In the structure of diborane (B_2H_6),the num | vedclass

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(B) The structure of diborane $(B_2H_6)$ consists of two boron atoms and six hydrogen atoms. There are $4$ terminal hydrogen atoms,each bonded to a bo

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$6$

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(B) The structure of diborane $(B_2H_6)$ consists of two boron atoms and six hydrogen atoms. There are $4$ terminal hydrogen atoms,each bonded to a boron atom by a $2$-centre-$2$-electron $(2c-2e)$ bond. Thus,$X = 4$. There are $2$ bridging hydrogen atoms,each involved in a $3$-centre-$2$-electron $(3c-2e)$ bond with the two boron atoms. Thus,$Y = 2$. The value of $(X+Y) = 4 + 2 = 6$.

In the structure of diborane $(B_2H_6)$,the number of $2$-centre-$2$-electron $(2c-2e)$ bonds is $X$ and the number of $3$-centre-$2$-electron $(3c-2e)$ bonds is $Y$. The value of $(X+Y)$ is:

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