In the study of a transistor as an amplifier, | vedclass

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Question

(B) The ratio of collector current $(I_C)$ to emitter current $(I_E)$ is known as the common-base current amplification factor,denoted by $\alpha$. Gi

Vedclass · Accepted Answer

$49$

Vedclass · Answer

(B) The ratio of collector current $(I_C)$ to emitter current $(I_E)$ is known as the common-base current amplification factor,denoted by $\alpha$. Given: $\alpha = \frac{I_C}{I_E} = 0.98$. The ratio of collector current $(I_C)$ to base current $(I_B)$ is known as the common-emitter current amplification factor,denoted by $\beta$. The relationship between $\alpha$ and $\beta$ is given by the formula: $\beta = \frac{\alpha}{1 - \alpha}$. Substituting the given value: $\beta = \frac{0.98}{1 - 0.98} = \frac{0.98}{0.02} = 49$. Therefore,the ratio of collector current to base current is $49$.

In the study of a transistor as an amplifier,the ratio of collector current to emitter current is $0.98$. Then,the ratio of collector current to base current will be:

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