In three-dimensional space,the equation 3y + | vedclass

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(A) The given equation is $3y + 4z = 0$.This is a linear equation in $x, y, z$ of the form $Ax + By + Cz + D = 0$,where $A=0, B=3, C=4, D=0$.Since the

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$A$ plane containing the $x$-axis

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(A) The given equation is $3y + 4z = 0$.This is a linear equation in $x, y, z$ of the form $Ax + By + Cz + D = 0$,where $A=0, B=3, C=4, D=0$.Since the equation is of the form $By + Cz = 0$,it represents a plane.For a plane to contain the $x$-axis,the coordinates of any point on the $x$-axis (which are of the form $(k, 0, 0)$) must satisfy the equation.Substituting $(k, 0, 0)$ into $3y + 4z = 0$,we get $3(0) + 4(0) = 0$,which is $0 = 0$.Since the equation is satisfied for all values of $k$,the plane contains the $x$-axis.

In three-dimensional space,the equation $3y + 4z = 0$ represents:

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