In triangle ABC (Fig.),which of the following | vedclass

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(B) According to the triangle law of vector addition,in triangle $ABC$,we have:$\overrightarrow{ AB } + \overrightarrow{ BC } = \overrightarrow{ AC }$

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$\overrightarrow{ AB }+\overrightarrow{ BC }-\overrightarrow{ CA }=\overrightarrow{0}$

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(B) According to the triangle law of vector addition,in triangle $ABC$,we have:$\overrightarrow{ AB } + \overrightarrow{ BC } = \overrightarrow{ AC }$Now let us evaluate each option:$(A) \overrightarrow{ AB } + \overrightarrow{ BC } + \overrightarrow{ CA } = \overrightarrow{ AC } + \overrightarrow{ CA } = \overrightarrow{ AC } - \overrightarrow{ AC } = \overrightarrow{0}$. This is true.$(B) \overrightarrow{ AB } + \overrightarrow{ BC } - \overrightarrow{ CA } = \overrightarrow{ AC } - \overrightarrow{ CA } = \overrightarrow{ AC } + \overrightarrow{ AC } = 2\overrightarrow{ AC } 
eq \overrightarrow{0}$. This is not true.$(C) \overrightarrow{ AB } + \overrightarrow{ BC } - \overrightarrow{ AC } = \overrightarrow{ AC } - \overrightarrow{ AC } = \overrightarrow{0}$. This is true.$(D) \overrightarrow{ AB } - \overrightarrow{ CB } + \overrightarrow{ CA } = \overrightarrow{ AB } + \overrightarrow{ BC } + \overrightarrow{ CA } = \overrightarrow{ AC } + \overrightarrow{ CA } = \overrightarrow{0}$. This is true.Therefore,the statement that is not true is $(B)$.

In triangle $ABC$ (Fig.),which of the following is not true:

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