In triangles ABC and PQR,AB = AC,angle C = an | vedclass

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(C) Given: In $	riangle ABC$,$AB = AC$. Therefore,$\angle B = \angle C$ (Angles opposite to equal sides are equal).Given: $\angle C = \angle P$ and $

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isosceles but not congruent

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(C) Given: In $	riangle ABC$,$AB = AC$. Therefore,$\angle B = \angle C$ (Angles opposite to equal sides are equal).Given: $\angle C = \angle P$ and $\angle B = \angle Q$.Since $\angle B = \angle C$,we have $\angle Q = \angle P$.In $	riangle PQR$,since $\angle Q = \angle P$,the sides opposite to these angles must be equal,so $PR = QR$. Thus,$	riangle PQR$ is an isosceles triangle.However,we do not have enough information (such as a side length or a specific angle measure) to prove that $	riangle ABC \cong 	riangle PQR$. For example,the triangles could have different sizes while maintaining the same angle relationships.Therefore,both triangles are isosceles,but they are not necessarily congruent.

In triangles $ABC$ and $PQR$,$AB = AC$,$\angle C = \angle P$ and $\angle B = \angle Q$. The two triangles are

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