In which of the following arrangements is the order $NOT$ according to the property indicated against it?

  • A
    $A$. $Al^{3+} < Mg^{2+} < Na^{+} < F^{-}$ : Increasing ionic size
  • B
    $B$. $B < C < N < O$ : Increasing first ionization enthalpy
  • C
    $C$. $I < Br < F < Cl$ : Increasing electron gain enthalpy (with negative sign)
  • D
    $D$. $Li < Na < K < Rb$ : Increasing metallic radius

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Similar Questions

The statement that is true for the long form of the periodic table is

Which of the following orders is $CORRECT$?

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Consider the following values of $IE$ $(eV)$ for elements $W$ and $X$:
Element$IE_1$$IE_2$$IE_3$$IE_4$
$W$$10.5$$15.5$$24.9$$79.8$
$X$$8$$14.8$$78.9$$105.8$

Other two elements $Y$ and $Z$ have outer electronic configuration $ns^2 np^4$ and $ns^2 np^5$ respectively. According to the given information,which of the following compound$(s)$ is/are not possible?
$(a) W_2Y_3, (b) X_2Y_3, (c) WZ_2, (d) XZ_2$

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Given below are two statements:
Statement $I$: The second ionisation enthalpy of $Na$ is larger than the corresponding ionisation enthalpy of $Mg$.
Statement $II$: The ionic radius of $O^{2-}$ is larger than that of $F^{-}$.
In the light of the above statements, choose the correct answer from the options given below.

Assign true $(T)$ or false $(F)$ for the following statements and select the correct option for your answer:
$(I)$ $I.P.$ of $O_{(g)}$ is less than $I.P.$ of $O^{-}_{(g)}$
$(II)$ $I.P.$ of $Ne_{(g)}$ is greater than $I.P.$ of $Ne^{+}_{(g)}$
$(III)$ $E.A.$ of $O^{+}_{(g)}$ is greater than $E.A.$ of $O_{(g)}$
$(IV)$ $I.P.$ of $N_{(g)}$ is greater than $I.P.$ of $N^{+}_{(g)}$

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