In which of the following cases,A=B? | vedclass

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(B) Two sets $A$ and $B$ are said to be equal if they contain exactly the same elements.Option $A$: $A=\{12, 14, 16\}$ and $B=\{16, 18, 20\}$. Since $

Vedclass · Accepted Answer

$A=\phi, B=\{\}$

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(B) Two sets $A$ and $B$ are said to be equal if they contain exactly the same elements.Option $A$: $A=\{12, 14, 16\}$ and $B=\{16, 18, 20\}$. Since $12 \in A$ but $12 
otin B$,$A 
eq B$.Option $B$: $A=\phi$ (empty set) and $B=\{\}$ (empty set). Both sets contain no elements,so $A=B$.Option $C$: $A=\{x: x \in W 	ext{ and } x Option $D$: $A=\{x: x 	ext{ is a day of the week beginning with } S\} = \{	ext{Sunday, Saturday}\}$. $B=\{	ext{Sunday}\}$. Since $\{	ext{Sunday, Saturday}\} 
eq \{	ext{Sunday}\}$,$A 
eq B$.Therefore,both $B$ and $C$ (if interpreted as empty) are technically equal,but $A=\phi$ and $B=\{\}$ is the standard definition of equality for empty sets.

In which of the following cases,$A=B$?

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