In which of the following changes is there no change in the hybridisation of the central atom?

  • A
    $C_2H_4 \xrightarrow{H_2 / Ni} C_2H_6$
  • B
    $PCl_5 + Cl^{-} \longrightarrow PCl_6^{-}$
  • C
    $BF_3 + F^{-} \longrightarrow BF_4^{-}$
  • D
    $NH_3 + H^{+} \longrightarrow NH_4^{+}$

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$sp^3$ hybridisation is found in

$H - C \equiv C - C \equiv C - CH_3$
Compare the bond lengths $a$ and $b$.

Describe the hybridization in $PCl_{5}$. Why are the axial bonds longer as compared to equatorial bonds?

Difficult
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The $C-H$ bond distance is the longest in

$KI + MnO_2 + H_2SO_4 \to$ Vapours $(B) +$ other products
Vapours $(B) + K_2S_2O_8 \to (C) + (D)$
$(D) \xrightarrow{(B)}$ Brown $(E)$
Hybridisation of central atom in $(E)$ is

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