In which of the following compounds,the C-Cl | vedclass

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(A) The stability of a carbocation is determined by factors like resonance,hyperconjugation,and the inductive effect. $1$. $C_6H_5CH_2Cl$ ionizes to f

Vedclass · Accepted Answer

$C_6H_5CH_2Cl$

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(A) The stability of a carbocation is determined by factors like resonance,hyperconjugation,and the inductive effect. $1$. $C_6H_5CH_2Cl$ ionizes to form the benzyl carbocation $(C_6H_5CH_2^+)$,which is highly stabilized by resonance with the benzene ring. $2$. $(CH_3)_3C-Cl$ forms a tertiary carbocation,which is stabilized by hyperconjugation and the inductive effect of three methyl groups. $3$. $(CH_3)_2CH-Cl$ forms a secondary carbocation,which is less stable than the tertiary one. $4$. $O_2NCH_2CH_2Cl$ forms a primary carbocation,which is further destabilized by the electron-withdrawing nitro group. Comparing the benzyl carbocation and the tertiary carbocation,the resonance stabilization provided by the phenyl ring in the benzyl carbocation makes it significantly more stable than the simple alkyl-substituted tertiary carbocation. Therefore,$C_6H_5CH_2Cl$ gives the most stable carbonium ion.

In which of the following compounds,the $C-Cl$ bond ionisation shall give the most stable carbonium ion?

Similar Questions

Which of the following is most likely to undergo a favorable hydride shift?

The correct stability order of the following carbocations is:
$I$. $H_2C^+-CH=CH-CH_3$
$II$. $H_2C^+-CH=CH-BMe_2$
$III$. $H_2C^+-CH=CH-NMe_2$
$IV$. $H_2C^+-CH=CH-OMe$

The correct order of stability of the given carbocations is:

Which of the following is the most stable carbocation?

Which of the following carbocations is the most stable?

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