The correct stability order of the following | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The stability of carbocations is determined by the electron-donating or electron-withdrawing nature of the substituents attached to the conjugated

Vedclass · Accepted Answer

$III > IV > I > II$

Vedclass · Answer

(C) The stability of carbocations is determined by the electron-donating or electron-withdrawing nature of the substituents attached to the conjugated system.$1$. In $III$ and $IV$, the groups $-NMe_2$ and $-OMe$ show a strong $+R$ (resonance) effect, which stabilizes the carbocation significantly.$2$. Since nitrogen is less electronegative than oxygen, the lone pair on $N$ is more easily donated, making $-NMe_2$ a stronger $+R$ group than $-OMe$. Thus, $III > IV$.$3$. In $I$, the $-CH_3$ group shows a weak $+I$ (inductive) effect and hyperconjugation, providing moderate stability.$4$. In $II$, the $-BMe_2$ group has an empty $p$-orbital and shows a $-R$ effect, which destabilizes the carbocation.$5$. Therefore, the correct stability order is $III > IV > I > II$.

Column $-I$	Column $-II$
$A$. Free radical	$1$. Trigonal planar
$B$. Carbocation	$2$. Pyramidal
$C$. Carbanion	$3$. Linear

The correct stability order of the following carbocations is:
$I$. $H_2C^+-CH=CH-CH_3$
$II$. $H_2C^+-CH=CH-BMe_2$
$III$. $H_2C^+-CH=CH-NMe_2$
$IV$. $H_2C^+-CH=CH-OMe$

Similar Questions

What is the correct order of stability for the given carbocations?
$(i) \ CH_3^+ \quad (ii) \ CH_3CH_2^+ \quad (iii) \ CH_3OCH_2^+$

Match the intermediates given in Column $-I$ with their probable structure in Column $-II$.

Column $-I$ Column $-II$

$A$. Free radical $1$. Trigonal planar

$B$. Carbocation $2$. Pyramidal

$C$. Carbanion $3$. Linear

Which of the following has an unstable enol form?

$CH_3-C(CH_3)_2-CH_2-CH_2^+ \to CH_3-C^+(CH_3)-CH(CH_3)-CH_3$
How many $H^-$ shifts are involved in the above rearrangement?

Which of the following carbocations is the most stable?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct stability order of the following carbocations is:$I$. $H_2C^+-CH=CH-CH_3$$II$. $H_2C^+-CH=CH-BMe_2$$III$. $H_2C^+-CH=CH-NMe_2$$IV$. $H_2C^+-CH=CH-OMe$