Match the intermediates given in Column $-I$ with their probable structure in Column $-II$.

Column $-I$	Column $-II$
$A$. Free radical	$1$. Trigonal planar
$B$. Carbocation	$2$. Pyramidal
$C$. Carbanion	$3$. Linear

(A-1, B-1, C-2) $A-1, B-1, C-2$
$A$. Free radicals are formed by homolytic cleavage and they are trigonal planar.
$B$. Carbocations are formed by heterolytic cleavage,where the central carbon is $sp^2$ hybridized,resulting in a trigonal planar geometry.
$C$. Carbanions have a lone pair of electrons on the central carbon,which is $sp^3$ hybridized,resulting in a pyramidal geometry.