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(C) The stability of the transition state in these $S_N1$ type dissociation steps is directly related to the stability of the resulting carbocation in

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$1 < 3 < 2$

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(C) The stability of the transition state in these $S_N1$ type dissociation steps is directly related to the stability of the resulting carbocation intermediate.Step $1$ produces a methyl carbocation $(CH_3^+)$,which is the least stable.Step $3$ produces an isopropyl carbocation $((CH_3)_2CH^+)$,which is a secondary $(2^o)$ carbocation.Step $2$ produces a tert-butyl carbocation $((CH_3)_3C^+)$,which is a tertiary $(3^o)$ carbocation.Since the stability order of carbocations is $3^o > 2^o > 1^o$ (methyl),the stability of the transition states follows the same order: $1 < 3 < 2$.

Rank the transition states that occur during the following reaction steps in order of increasing stability (least $\to$ most stable):
$1.$ $CH_3-O^+H_2 \to CH_3^+ + H_2O$
$2.$ $(CH_3)_3C-O^+H_2 \to (CH_3)_3C^+ + H_2O$
$3.$ $(CH_3)_2CH-O^+H_2 \to (CH_3)_2CH^+ + H_2O$

Similar Questions

The orbital picture of a triplet carbene can be drawn as

Consider the following compounds:
$(I)$ $(CH_3)_3C-CH^{\bullet}-C_6H_5$
$(II)$ $(C_6H_5)_3C^{\bullet}$
$(III)$ $2$-methylbicyclo$[2.2.1]$hept$-2-$yl radical (as shown in the image)
Hyperconjugation occurs in:

The orbital picture of a singlet carbene $(:CH_2)$ can be drawn as:

Compare the stability of the following free radicals:
$(1)$ $CH_3 - \dot{CH} - CH_3$
$(2)$ $C_6H_5 - \dot{CH_2}$
$(3)$ $\dot{CH_2} - CH(CH_3)_2$
$(4)$ $\dot{CH_2} - CH_3$

Which of the following is not expected to be an intermediate of the following reaction?

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Rank the transition states that occur during the following reaction steps in order of increasing stability (least $\to$ most stable):$1.$ $CH_3-O^+H_2 \to CH_3^+ + H_2O$$2.$ $(CH_3)_3C-O^+H_2 \to (CH_3)_3C^+ + H_2O$$3.$ $(CH_3)_2CH-O^+H_2 \to (CH_3)_2CH^+ + H_2O$