Compare the stability of the following free r | vedclass

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(B) The stability of free radicals is determined by factors such as resonance,hyperconjugation,and the inductive effect.$(II)$ $C_6H_5 - \dot{CH_2}$ (

Vedclass · Accepted Answer

$II > I > IV > III$

Vedclass · Answer

(B) The stability of free radicals is determined by factors such as resonance,hyperconjugation,and the inductive effect.$(II)$ $C_6H_5 - \dot{CH_2}$ (Benzyl radical) is resonance-stabilized by the phenyl ring,making it the most stable.$(I)$ $CH_3 - \dot{CH} - CH_3$ is a secondary $(2^{\circ})$ radical with $6$ alpha-hydrogen atoms,providing significant hyperconjugation.$(IV)$ $\dot{CH_2} - CH_3$ is a primary $(1^{\circ})$ radical with $3$ alpha-hydrogen atoms.$(III)$ $\dot{CH_2} - CH(CH_3)_2$ is a primary $(1^{\circ})$ radical with only $1$ alpha-hydrogen atom.Comparing the hyperconjugation,the order of stability for the remaining radicals is $I > IV > III$.Thus,the overall order of stability is $II > I > IV > III$.

Label	Carbocation
$1$	$CH_3-CH^+-CH_3$
$2$	$CH_3^+$
$3$	$(CH_3)_3C^+$
$4$	$CH_3-CH_2^+$

Compare the stability of the following free radicals:
$(1)$ $CH_3 - \dot{CH} - CH_3$
$(2)$ $C_6H_5 - \dot{CH_2}$
$(3)$ $\dot{CH_2} - CH(CH_3)_2$
$(4)$ $\dot{CH_2} - CH_3$

Similar Questions

Arrange the following carbocations in the increasing order of stability with respect to their labels:
Label Carbocation
$1$ $CH_3-CH^+-CH_3$
$2$ $CH_3^+$
$3$ $(CH_3)_3C^+$
$4$ $CH_3-CH_2^+$

Which of the following intermediates is more stable?

Which of the following is the most stable carbocation?

Which of the following carbocations lacks hyperconjugative stability?

Arrange the following carbocations in decreasing order of stability.

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Compare the stability of the following free radicals:$(1)$ $CH_3 - \dot{CH} - CH_3$$(2)$ $C_6H_5 - \dot{CH_2}$$(3)$ $\dot{CH_2} - CH(CH_3)_2$$(4)$ $\dot{CH_2} - CH_3$