Arrange the following carbocations in decreas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The stability of carbocations is determined by resonance and inductive effects.In structure $B$,the positive charge is on the carbon atom adjacent

Vedclass · Accepted Answer

$B > A > C$

Vedclass · Answer

(D) The stability of carbocations is determined by resonance and inductive effects.In structure $B$,the positive charge is on the carbon atom adjacent to the oxygen atom. The lone pair on the oxygen atom can donate electron density through resonance,which significantly stabilizes the carbocation.In structure $C$,the positive charge is on the carbon atom at the $\beta$-position relative to the oxygen atom. The oxygen atom exerts an electron-withdrawing inductive effect ($-I$ effect),which destabilizes the carbocation.In structure $A$,the carbocation is a simple secondary carbocation without any adjacent heteroatom effects.Therefore,the stability order is $B > A > C$.

Arrange the following carbocations in decreasing order of stability.

Similar Questions

The increasing order of stability of the following free radicals is:

In the organic reaction by fission of bond,which intermediate species are formed? Name these species and explain their stability.

How many $1,2-$ shifts take place in the following carbocation to reach the most stable form?

Which one of the following species is most stable?

$p$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module