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(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} 	imes (V - N)$,where $V$ is the nu

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$XeF_2$

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(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} 	imes (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of electrons involved in bonding (monovalent atoms).$1$. For $NH_3$: Central atom $N$ has $5$ valence electrons. It forms $3$ bonds. $	ext{Lone pairs} = \frac{1}{2} 	imes (5 - 3) = 1$.$2$. For $H_2O$: Central atom $O$ has $6$ valence electrons. It forms $2$ bonds. $	ext{Lone pairs} = \frac{1}{2} 	imes (6 - 2) = 2$.$3$. For $ClF_3$: Central atom $Cl$ has $7$ valence electrons. It forms $3$ bonds. $	ext{Lone pairs} = \frac{1}{2} 	imes (7 - 3) = 2$.$4$. For $XeF_2$: Central atom $Xe$ has $8$ valence electrons. It forms $2$ bonds. $	ext{Lone pairs} = \frac{1}{2} 	imes (8 - 2) = 3$.Thus,$XeF_2$ has the maximum number of lone pairs $(3)$ on the central atom.

List-$I$	List-$II$
$(A)$ $PCl_3$	$(I)$ Square planar
$(B)$ $BF_3$	$(II)$ $T$-shape
$(C)$ $ClF_3$	$(III)$ Trigonal pyramidal
$(D)$ $XeF_4$	$(IV)$ See-saw
	$(V)$ Trigonal planar

In which of the following molecules,the maximum number of lone pairs is present on the central atom?

Similar Questions

Between the dichloronitronium ion $[ONCl_2]^+$ and thionyl chloride $(OSCl_2)$,which has a higher $Cl-\hat{X}-Cl$ bond angle? (where $X$ is the central atom $N$ or $S$)

Match the molecules in List-$I$ with their correct geometries in List-$II$ according to $VSEPR$ theory:
List-$I$ List-$II$
$(A)$ $PCl_3$ $(I)$ Square planar
$(B)$ $BF_3$ $(II)$ $T$-shape
$(C)$ $ClF_3$ $(III)$ Trigonal pyramidal
$(D)$ $XeF_4$ $(IV)$ See-saw
$(V)$ Trigonal planar

Which of the following has the smallest bond angle?

Which of the following is not linear?

What are the number of lone pairs of electrons on the central atom in $XeF_2$,$XeF_4$,and $XeF_6$ respectively?

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