In which one of the following species does th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The hybridization of the central atom can be determined using the formula $H = \frac{1}{2} [V + X - C + A]$,where $V$ is the number of valence ele

Vedclass · Accepted Answer

$SbCl_5^{2-}$

Vedclass · Answer

(C) The hybridization of the central atom can be determined using the formula $H = \frac{1}{2} [V + X - C + A]$,where $V$ is the number of valence electrons,$X$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.$1. SF_4: H = \frac{1}{2} [6 + 4] = 5 \rightarrow sp^3d$$2. I_3^-: H = \frac{1}{2} [7 + 2 + 1] = 5 \rightarrow sp^3d$$3. PCl_5: H = \frac{1}{2} [5 + 5] = 5 \rightarrow sp^3d$$4. SbCl_5^{2-}: H = \frac{1}{2} [5 + 5 + 2] = 6 \rightarrow sp^3d^2$Thus,$SbCl_5^{2-}$ has a different hybridization $(sp^3d^2)$ compared to the others $(sp^3d)$.

List-$I$	List-$II$
$(a)$ $SF_6$	$(i)$ $sp^3d^2$
$(b)$ $PCl_5$	(ii) $sp^3d$
$(c)$ $XeF_4$	(iii) $sp^3d^3$
$(d)$ $IF_7$	(iv) $sp^3d^2$

In which one of the following species does the central atom have a type of hybridization that is not the same as that present in the other three?

Similar Questions

The hybridisation of $Xe$ and the number of lone pairs of electrons on it in $XeF_6$ are

Which of the following is incorrectly matched?
Hybridisation $\to$ Geometry $\to$ Orbitals used

What is the hybridization of carbon in graphite and diamond,respectively?

Match the following:
List-$I$ List-$II$
$(a)$ $SF_6$ $(i)$ $sp^3d^2$
$(b)$ $PCl_5$ (ii) $sp^3d$
$(c)$ $XeF_4$ (iii) $sp^3d^3$
$(d)$ $IF_7$ (iv) $sp^3d^2$

The correct answer is:

Why is the bond angle in $CH_4$ not $90^{\circ}$,even though the outermost $p$-orbitals of carbon are at $90^{\circ}$ to each other?

Vedclass Test Series

Exam Paper Generator

Online Exam Module