Which of the following is the incorrect order | vedclass

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(C) To determine the bond angle,we consider hybridization,lone pairs,and electronegativity of the central and surrounding atoms. $1$. For option $A$:

Vedclass · Accepted Answer

$XeO_4 > ClO^{-}_4 > SO^{2-}_4 > CF_4$

Vedclass · Answer

(C) To determine the bond angle,we consider hybridization,lone pairs,and electronegativity of the central and surrounding atoms. $1$. For option $A$: $OCl_2$ $(111^{\circ})$,$SF_2$ $(103^{\circ})$,$AsH_3$ $(92^{\circ})$,$H_2Se$ $(91^{\circ})$. The order is correct. $2$. For option $B$: $NH_3$ $(107^{\circ})$,$PF_3$ $(96^{\circ})$,$PH_3$ $(93^{\circ})$,$H_2S$ $(92^{\circ})$. The order is correct. $3$. For option $C$: All these species ($XeO_4$,$ClO^{-}_4$,$SO^{2-}_4$,$CF_4$) have $sp^3$ hybridization and a tetrahedral geometry. In an ideal tetrahedral geometry,the bond angle is $109^{\circ} 28'$. Since all have the same geometry,their bond angles are equal. Therefore,the order $XeO_4 > ClO^{-}_4 > SO^{2-}_4 > CF_4$ is incorrect because they are all equal. Thus,option $C$ represents the incorrect order.

Molecule	Geometry
$(A)$ $XeF_2$	$1$. Trigonal pyramidal
$(B)$ $XeO_3$	$2$. Distorted octahedral
$(C)$ $XeF_6$	$3$. Linear
$(D)$ $XeOF_4$	$4$. Square pyramidal

Which of the following is the incorrect order of bond angle?

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