Incorrect statement regarding N(SiH_3)_3 is | vedclass

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(NONE) The molecule $N(SiH_3)_3$ (trisilylamine) has a planar geometry around the nitrogen atom due to $p\pi-d\pi$ back-bonding from the lone pair of

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$N-Si$ bond length is less than a single bond

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(NONE) The molecule $N(SiH_3)_3$ (trisilylamine) has a planar geometry around the nitrogen atom due to $p\pi-d\pi$ back-bonding from the lone pair of $N$ into the vacant $d$-orbitals of $Si$.Because of this back-bonding,the $N-Si$ bond acquires partial double bond character,making it shorter than a typical $N-Si$ single bond.$N(SiH_3)_3$ is a much weaker base than $NH_3$ because the lone pair on $N$ is involved in back-bonding and is not available for donation.The central $N$ atom is $sp^2$ hybridized,while the $Si$ atoms are $sp^3$ hybridized.Therefore,the statement that it is associated with two types of hybridization of central atoms is correct.All statements $A$,$B$,$C$,and $D$ are actually correct descriptions of $N(SiH_3)_3$. However,if forced to choose the most technically 'incorrect' phrasing in some contexts,it is often noted that $N(SiH_3)_3$ is planar,but the $SiH_3$ groups themselves are tetrahedral. Given the standard options,all are factually true. If this is a multiple-choice question where one must be false,there may be an error in the question source,but based on chemical principles,all provided statements are correct.

Incorrect statement regarding $N(SiH_3)_3$ is

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