Inorganic benzene reacts with $HCl$ to form a compound $B_3N_3H_9Cl_3$. The protonation occurs at

  • A
    $B^{-}$ atom
  • B
    $N^{+}$ atom
  • C
    First at $B^{-}$ atom then rearranges into $N^{+}$ atom
  • D
    First at $N^{+}$ atom then rearranges into $B^{-}$ atom

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