When borax is heated with $CoO$ on a platinum loop,the blue coloured bead formed is largely due to
- A$B_{2}O_{3}$
- B$Co(BO_{2})_{2}$
- C$CoB_{4}O_{7}$
- D$Co[B_{4}O_{5}(OH)_{4}]$
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Similar Questions
In which of the following reactions is hydrogen one of the products?
$i$. $2NaBH_4 + I_2 \longrightarrow$
$ii$. $2BF_3 + 6NaH \xrightarrow{450 \ K}$
$iii$. $4BF_3 + 3LiAlH_4 \longrightarrow$
$iv$. $3B_2H_6 + 6NH_3 \xrightarrow{\text{heat}} 2B_3N_3H_6 + 12H_2$
$i$. $2NaBH_4 + I_2 \longrightarrow$
$ii$. $2BF_3 + 6NaH \xrightarrow{450 \ K}$
$iii$. $4BF_3 + 3LiAlH_4 \longrightarrow$
$iv$. $3B_2H_6 + 6NH_3 \xrightarrow{\text{heat}} 2B_3N_3H_6 + 12H_2$
Aluminium $(III)$ chloride forms a dimer because ........
Medium
View SolutionThe bonding in diborane $(B_2H_6)$ can be described by
The element that combines with oxygen to give an amphoteric oxide is
MediumKVPY 2014
View SolutionThe incorrect statement regarding $X$ in the given reaction is:
$BF_3 + LiAlH_4 \xrightarrow{\text{Ether}} X + LiF + AlF_3$
$BF_3 + LiAlH_4 \xrightarrow{\text{Ether}} X + LiF + AlF_3$
Difficult
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