Ionic conductance of $Ga^{3+}$ ions and $NO_3^-$ ions at infinite dilution are $120 \, \Omega^{-1} \, cm^2 \, mol^{-1}$ and $50 \, \Omega^{-1} \, cm^2 \, mol^{-1}$ respectively. Equivalent conductance of $Ga(NO_3)_3$ at infinite dilution will be ........... $\Omega^{-1} \, cm^2 \, eq^{-1}$.

The molar conductance of an infinitely dilute solution of ammonium chloride was found to be $185 \ S \ cm^2 \ mol^{-1}$ and the ionic conductance of hydroxyl and chloride ions are $170$ and $70 \ S \ cm^2 \ mol^{-1}$,respectively. If molar conductance of $0.02 \ M$ solution of ammonium hydroxide is $85.5 \ S \ cm^2 \ mol^{-1}$,its degree of dissociation is given by $x \times 10^{-1}$. The value of $x$ is $...........$ $(Nearest \ integer)$

The ionic conductance of the following cations in a given concentration is in the order:

The resistance of a conductivity cell filled with $0.1 \ M$ $KCl$ solution is $100 \ \Omega$. If the resistance of the same cell when filled with $0.02 \ M$ $KCl$ solution is $520 \ \Omega$,the molar conductivity of $0.02 \ M$ solution (in $S \ cm^2 \ mol^{-1}$) is (Given: conductivity of $0.1 \ M$ $KCl$ solution $= 1.29 \ S \ m^{-1}$)

Resistance of a cell containing $0.02 \ M \ KCl$ solution is $164 \ \Omega$. If the cell is filled with $0.05 \ M \ AgNO_3$,the resistance becomes $75.8 \ \Omega$. Calculate the following: [Conductivity of $0.02 \ M \ KCl = 2.768 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$] $(i)$ Conductivity of $0.05 \ M \ AgNO_3$ (ii) Molar conductivity of $AgNO_3$ solution.

How can the ionic conductivity of an unknown solution be determined?