The ionization energy of hydrogen is 13.6 , e | vedclass

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(B) The ionization energy $E$ of a hydrogen atom is related to the Rydberg constant $R$ by the formula $E = Rch$,where $c$ is the speed of light and $

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$10^7 \, m^{-1}$

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(B) The ionization energy $E$ of a hydrogen atom is related to the Rydberg constant $R$ by the formula $E = Rch$,where $c$ is the speed of light and $h$ is Planck's constant.Rearranging for $R$,we get $R = \frac{E}{ch}$.Given $E = 13.6 \, eV = 13.6 	imes 1.6 	imes 10^{-19} \, J$,$c = 3 	imes 10^8 \, m/s$,and $h = 6.6 	imes 10^{-34} \, J \cdot s$.Substituting these values:$R = \frac{13.6 	imes 1.6 	imes 10^{-19}}{3 	imes 10^8 	imes 6.6 	imes 10^{-34}}$$R = \frac{21.76 	imes 10^{-19}}{19.8 	imes 10^{-26}}$$R \approx 1.098 	imes 10^7 \, m^{-1}$.Thus,the order of magnitude of $R$ is $10^7 \, m^{-1}$.

The ionization energy of hydrogen is $13.6 \, eV$. If $h = 6.6 \times 10^{-34} \, J \cdot s$,the order of magnitude of the Rydberg constant $R$ will be:

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