It is found that for every $10^{\circ}C$ rise in temperature,the rate of the reaction doubles itself. This is mainly because

  • A
    The speed of the reactants doubles for every $10^{\circ}C$ rise in temperature.
  • B
    The fraction of the molecules forming the activated complex doubles itself.
  • C
    The concentration doubles itself.
  • D
    The collision frequency doubles itself.

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Similar Questions

The rate constant for the reaction,$COCl_{2(g)} \longrightarrow CO_{(g)} + Cl_{2(g)}$ is given by $\ln[k / (min^{-1})] = -11067 / T(K) + 31.33$. The temperature at which the rate of this reaction will be doubled from that at $25^{\circ} C$ is $..... \, ^{\circ} C$.

$A$ catalyst:

For an effective collision to occur,the colliding molecules must possess:

$A \rightarrow B$
The rate constants of the above reaction at $200 \, K$ and $300 \, K$ are $0.03 \, min^{-1}$ and $0.05 \, min^{-1}$ respectively. The activation energy for the reaction is $.... \, J$ (Nearest integer).
(Given: $\ln 10 = 2.3$,$R = 8.3 \, J \, K^{-1} \, mol^{-1}$,$\log 5 = 0.70$,$\log 3 = 0.48$,$\log 2 = 0.30$)

The specific rate constant of a $1^{st}$ order reaction depends on the

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