Length of a rectangle is twice of its breadth | vedclass

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(B) Let the breadth of the rectangle be $b \, m$.Given that the length $l = 2b$.The area of the rectangle is given by $l 	imes b = 18 \, m^2$.Substit

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$18$

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(B) Let the breadth of the rectangle be $b \, m$.Given that the length $l = 2b$.The area of the rectangle is given by $l 	imes b = 18 \, m^2$.Substituting $l = 2b$,we get $(2b) 	imes b = 18$.$2b^2 = 18 \Rightarrow b^2 = 9 \Rightarrow b = 3 \, m$.Thus,the length $l = 2 	imes 3 = 6 \, m$.The perimeter of a rectangle is calculated as $2(l + b)$.Perimeter $= 2(6 + 3) = 2(9) = 18 \, m$.

Length of a rectangle is twice of its breadth. Area of the rectangle is $18 \, m^2$. What would be its perimeter? (in $m$)

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