मान लीजिए कि $a_{1}, a_{2}, \dots, a_{n}$ निश्चित वास्तविक संख्याएँ हैं और एक फलन $f(x) = (x - a_{1})(x - a_{2}) \dots (x - a_{n})$ परिभाषित है। $\lim_{x \to a_{1}} f(x)$ क्या है? किसी $a \neq a_{1}, a_{2}, \dots, a_{n}$ के लिए,$\lim_{x \to a} f(x)$ की गणना करें।

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दिया गया फलन $f(x) = (x - a_{1})(x - a_{2}) \dots (x - a_{n})$ है।
$\lim_{x \to a_{1}} f(x) = \lim_{x \to a_{1}} [(x - a_{1})(x - a_{2}) \dots (x - a_{n})]$
$= (a_{1} - a_{1})(a_{1} - a_{2}) \dots (a_{1} - a_{n}) = 0 \times (a_{1} - a_{2}) \dots (a_{1} - a_{n}) = 0$.
अतः,$\lim_{x \to a_{1}} f(x) = 0$.
अब,$a \neq a_{1}, a_{2}, \dots, a_{n}$ के लिए,
$\lim_{x \to a} f(x) = \lim_{x \to a} [(x - a_{1})(x - a_{2}) \dots (x - a_{n})]$
$= (a - a_{1})(a - a_{2}) \dots (a - a_{n})$.
अतः,$\lim_{x \to a} f(x) = (a - a_{1})(a - a_{2}) \dots (a - a_{n})$.

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