Let y = f(x) = ax^2 + 2bx + c (where a, b, c | vedclass

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(B) Given the quadratic function $f(x) = ax^2 + 2bx + c$.We are given that $f(x) = 0$ has imaginary roots,which implies the discriminant $D = (2b)^2 -

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$c < 0$

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(B) Given the quadratic function $f(x) = ax^2 + 2bx + c$.We are given that $f(x) = 0$ has imaginary roots,which implies the discriminant $D = (2b)^2 - 4ac We are also given that $4a + 4b + c Since $f(x)$ has imaginary roots,the parabola $y = f(x)$ does not intersect the $x$-axis. This means $f(x)$ is either always positive (if $a > 0$) or always negative (if $a If $a > 0$,then $f(x) > 0$ for all $x$,which contradicts $f(2) Since $a < 0$ and $f(x)$ is always negative,the entire parabola lies below the $x$-axis. The $y$-intercept is $f(0) = c$. Since the entire graph is below the $x$-axis,the $y$-intercept must be negative. Therefore,$c < 0$.

Let $y = f(x) = ax^2 + 2bx + c$ (where $a, b, c \in R$ and $a \neq 0$). If $f(x) = 0$ has imaginary roots and $4a + 4b + c < 0$,then which of the following is true?

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