Let $P$ be a point inside a $\triangle ABC$ with $\angle ABC = 90^{\circ}$. Let $P_1$ and $P_2$ be the images of $P$ under reflection in $AB$ and $BC$ respectively. The distance between the circumcenters of $\triangle ABC$ and $\triangle P_1PP_2$ is

  • A
    $\frac{AB}{2}$
  • B
    $\frac{AP+BP+CP}{3}$
  • C
    $\frac{AC}{2}$
  • D
    $\frac{AB+BC+AC}{2}$

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