(A) The midpoint of the segment joining $(-4, 6)$ and $(8, 8)$ is $(\frac{-4+8}{2}, \frac{6+8}{2}) = (2, 7)$.The slope of the line joining $(-4, 6)$ a

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(A) The midpoint of the segment joining $(-4, 6)$ and $(8, 8)$ is $(\frac{-4+8}{2}, \frac{6+8}{2}) = (2, 7)$.The slope of the line joining $(-4, 6)$ and $(8, 8)$ is $m = \frac{8-6}{8-(-4)} = \frac{2}{12} = \frac{1}{6}$.The slope of the perpendicular bisector is $m' = -\frac{1}{m} = -6$.The equation of the line passing through $(2, 7)$ with slope $-6$ is $y - 7 = -6(x - 2)$.$y - 7 = -6x + 12$.$6x + y - 19 = 0$.

Class 11 Mathematics Straight Lines Foot of perpendicular, Image of a point and Reflexive properties

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The equation of the line bisecting perpendicularly the segment joining the points $(-4, 6)$ and $(8, 8)$ is

A
$6x + y - 19 = 0$
B
$y = 7$
C
$6x + 2y - 19 = 0$
D
$x + 2y - 7 = 0$

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Foot of perpendicular, Image of a point and Reflexive properties

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The equation of the line bisecting perpendicularly the segment joining the points $(-4, 6)$ and $(8, 8)$ is

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