Let A = {10, 11, 12, 14, 26} and let f: A rig | vedclass

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(C) Given the set $A = \{10, 11, 12, 14, 26\}$.We find the prime factorization for each element in $A$:$10 = 2 	imes 5$,so the highest prime factor i

Vedclass · Accepted Answer

$\{3, 5, 7, 11, 13\}$

Vedclass · Answer

(C) Given the set $A = \{10, 11, 12, 14, 26\}$.We find the prime factorization for each element in $A$:$10 = 2 	imes 5$,so the highest prime factor is $5$.$11 = 11$,so the highest prime factor is $11$.$12 = 2^2 	imes 3$,so the highest prime factor is $3$.$14 = 2 	imes 7$,so the highest prime factor is $7$.$26 = 2 	imes 13$,so the highest prime factor is $13$.Thus,the range of $f$ is the set of all these highest prime factors: $\{3, 5, 7, 11, 13\}$.Therefore,the correct option is $C$.

Let $A = \{10, 11, 12, 14, 26\}$ and let $f: A \rightarrow N$ be defined such that $f(a) = \text{highest prime factor of } a$,where $a \in A$. Then the range of $f$ is:

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