Let $C$ be the centre and $A$ be one end of a diameter of the circle $x^2+y^2-2x-4y-20=0$. If $P$ is a point such that $A$ divides $CP$ in the ratio $2:3$,then the locus of $P$ is

  • A
    $x^2+y^2-2x-4y-205=0$
  • B
    $2x^2+2y^2-4x-8y-405=0$
  • C
    $x^2+y^2-2x-4y-450=0$
  • D
    $4x^2+4y^2-8x-16y-605=0$

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