Let a and b be two unit vectors inclined at a | vedclass

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(A) Given that $a$ and $b$ are unit vectors,so $|a| = 1$ and $|b| = 1$.We know that $|a - b|^2 = |a|^2 + |b|^2 - 2|a||b|\cos	heta$.Substituting the v

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$\frac{1}{2}|a-b|$

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(A) Given that $a$ and $b$ are unit vectors,so $|a| = 1$ and $|b| = 1$.We know that $|a - b|^2 = |a|^2 + |b|^2 - 2|a||b|\cos	heta$.Substituting the values,we get $|a - b|^2 = 1^2 + 1^2 - 2(1)(1)\cos	heta = 2 - 2\cos	heta$.Using the trigonometric identity $1 - \cos	heta = 2\sin^2(	heta/2)$,we have $|a - b|^2 = 2(2\sin^2(	heta/2)) = 4\sin^2(	heta/2)$.Taking the square root on both sides,we get $|a - b| = 2\sin(	heta/2)$.Therefore,$\sin(	heta/2) = \frac{1}{2}|a - b|$.

Let $a$ and $b$ be two unit vectors inclined at an angle $\theta$,then $\sin(\theta/2)$ is equal to

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