Let $f(x) = (x - 3)^{2018}(x - 2)^{2019}, x \in R$. If $f(\alpha)$ is a relative maximum of $f$ at $x = \alpha$, then $2\alpha + 3f(\alpha) =$

  • A
    $\frac{20186}{4037}$
  • B
    $\frac{20186}{4037} - 3 \left( \frac{2018}{4037} \right)^{2018} \left( \frac{2019}{4037} \right)^{2019}$
  • C
    $6$
  • D
    $9$

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