Let $f: R \rightarrow R$ be differentiable at $x=0$. If $f(0)=0$ and $f'(0)=2$, then the value of $\lim _{x \rightarrow 0} \frac{1}{x} [f(x)+f(2 x)+f(3 x)+\ldots+f(2015 x)]$ is

  • A
    $2015$
  • B
    $0$
  • C
    $2015 \times 2016$
  • D
    $2015 \times 2014$

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