Let $A = \begin{bmatrix} x+2 & 3x \\ 3 & x+2 \end{bmatrix}$ and $B = \begin{bmatrix} x & 0 \\ 5 & x+2 \end{bmatrix}$. Then all solutions of the equation $\det(AB) = 0$ are:

  • A
    $1, -1, 0, 2$
  • B
    $1, 4, 0, -2$
  • C
    $1, -1, 4, 3$
  • D
    $-1, 4, 0, 3$

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