Let y = f(x) = 2x^{2} - 3x + 2. The different | vedclass

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(C) Given the function $f(x) = 2x^{2} - 3x + 2$. We need to find the differential $dy$ when $x$ changes from $x = 2$ to $x = 1.99$. Here, $x = 2$ and

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$-0.05$

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(C) Given the function $f(x) = 2x^{2} - 3x + 2$. We need to find the differential $dy$ when $x$ changes from $x = 2$ to $x = 1.99$. Here, $x = 2$ and $\Delta x = 1.99 - 2 = -0.01$. The derivative of the function is $f'(x) = \frac{d}{dx}(2x^{2} - 3x + 2) = 4x - 3$. At $x = 2$, $f'(2) = 4(2) - 3 = 8 - 3 = 5$. The differential $dy$ is given by the formula $dy = f'(x) \Delta x$. Substituting the values, $dy = f'(2) 	imes (-0.01) = 5 	imes (-0.01) = -0.05$. Thus, the differential of $y$ is $-0.05$.

Let $y = f(x) = 2x^{2} - 3x + 2$. The differential of $y$ when $x$ changes from $2$ to $1.99$ is

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