Let $\exp(x)$ denote the exponential function $e^x$. If $f(x) = \exp\left(x^{\frac{1}{x}}\right)$ for $x > 0$, then the minimum value of $f$ in the interval $[2, 5]$ is:

  • A
    $\exp\left(e^{\frac{1}{e}}\right)$
  • B
    $\exp\left(2^{\frac{1}{2}}\right)$
  • C
    $\exp\left(5^{\frac{1}{5}}\right)$
  • D
    $\exp\left(3^{\frac{1}{3}}\right)$

Explore More

Similar Questions

If $x$ is real,then the minimum value of $\frac{x^2-x+1}{x^2+x+1}$ is

Let $f(x) = |(x-1)(x^2-2x-3)| + x - 3$,$x \in R$. If $m$ and $M$ are respectively the number of points of local minimum and local maximum of $f$ in the interval $(0,4)$,then $m + M$ is equal to

If two sides of a triangle are given,then the area of the triangle will be maximum if the angle between the given sides is

For all real $x$,the minimum value of the function $f(x)=\frac{1-x+x^2}{1+x+x^2}$ is

$P$ and $Q$ are two points on a circle with center $C$ and radius $\alpha$. The angle $\angle PCQ = 2\theta$. The radius $r$ of the circle inscribed in the triangle $CPQ$ is maximum when:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo