Let $\sum_{k=1}^{n} a_{k} = \alpha n^{2} + \beta n$. If $a_{10} = 59$ and $a_{6} = 7a_{1}$, then $\alpha + \beta$ is equal to:

  • A
    $12$
  • B
    $3$
  • C
    $5$
  • D
    $7$

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