Let $O$ be the origin, $\vec{OP} = \vec{a}$ and $\vec{OQ} = \vec{b}$. If $R$ is the point on $\vec{OP}$ such that $\vec{OP} = 5\vec{OR}$, and $M$ is the point such that $\vec{OQ} = 5\vec{RM}$, then $\vec{PM}$ is equal to:

  • A
    $\frac{1}{5}(\vec{a}-4\vec{b})$
  • B
    $\frac{1}{5}(\vec{b}-4\vec{a})$
  • C
    $\frac{1}{5}(-\vec{a}+4\vec{b})$
  • D
    $\frac{1}{5}(-\vec{b}+4\vec{a})$

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If $a = \alpha \hat{i} + 3 \hat{j} - 6 \hat{k}$ and $b = 2 \hat{i} - \hat{j} + \beta \hat{k}$,then the values of $\alpha, \beta$ so that $a$ and $b$ may be collinear are

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