Let $f(x) = \frac{x - 1}{2x^2 - 7x + 5}$. Then:
- A$\lim_{x \to 1} f(x) = -\frac{1}{3}$
- B$\lim_{x \to 0} f(x) = -\frac{1}{5}$
- C$f(x) \neq 0$
- DAll of the above
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