Let $f(x) = (x-4)(x-5)(x-6)(x-7)$,then -

  • A
    $f'(x) = 0$ has four roots
  • B
    Three roots of $f'(x) = 0$ lie in $(4, 5) \cup (5, 6) \cup (6, 7)$
  • C
    The equation $f'(x) = 0$ has only one root
  • D
    Three roots of $f'(x) = 0$ lie in $(3, 4) \cup (4, 5) \cup (5, 6)$

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