Let the foci of the hyperbola coincide with the foci of the ellipse $\frac{x^{2}}{36}+\frac{y^{2}}{16}=1$. If the eccentricity of the hyperbola is $5$, then the length of its latus rectum is:

  • A
    $12$
  • B
    $16$
  • C
    $\frac{96}{\sqrt{5}}$
  • D
    $24\sqrt{5}$

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