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(B) Given that the number of elements in set $A$ is $n(A) = p$ and the number of elements in set $B$ is $n(B) = q$. The total number of elements in th

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$2^{pq}$

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(B) Given that the number of elements in set $A$ is $n(A) = p$ and the number of elements in set $B$ is $n(B) = q$. The total number of elements in the Cartesian product $A 	imes B$ is $n(A 	imes B) = n(A) 	imes n(B) = pq$. $A$ relation from set $A$ to set $B$ is a subset of $A 	imes B$. The total number of subsets of a set with $n$ elements is $2^n$. Therefore, the total number of relations from set $A$ to set $B$ is $2^{pq}$.

Let the number of elements of the sets $A$ and $B$ be $p$ and $q$, respectively. Then, the number of relations from the set $A$ to the set $B$ is

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