A light wave enters from medium 1 to medium 2 | vedclass

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(D) Let the velocity in medium $1$ be $v_1 = v$ and in medium $2$ be $v_2 = 2v$. According to Snell's Law,$\frac{\sin i}{\sin r} = \frac{v_1}{v_2} = \

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Total internal reflection is not possible

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(D) Let the velocity in medium $1$ be $v_1 = v$ and in medium $2$ be $v_2 = 2v$. According to Snell's Law,$\frac{\sin i}{\sin r} = \frac{v_1}{v_2} = \frac{v}{2v} = \frac{1}{2}$. For total internal reflection,the light must travel from a denser medium to a rarer medium. Here,$v_2 > v_1$,which means medium $2$ is rarer than medium $1$. Therefore,light must travel from medium $2$ to medium $1$ for total internal reflection to occur. Since the question states the light enters from medium $1$ to medium $2$ (denser to rarer is not possible here as $1$ is denser),total internal reflection cannot occur in this specific configuration. However,if we assume the question implies the critical angle calculation for the interface,$\sin C = \frac{v_1}{v_2} = \frac{1}{2}$,so $C = 30^{\circ}$. But since light is moving from a rarer to a denser medium $(v_1 < v_2)$,total internal reflection is physically impossible.

$A$ light wave enters from medium $1$ to medium $2$. Its velocity in the $2^{nd}$ medium is double that of the $1^{st}$ medium. For total internal reflection to occur,the angle of incidence must be greater than which of the following values?

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