Magnifying power of a simple microscope is (w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a simple microscope,the magnifying power $M$ is defined as the ratio of the angle subtended by the image at the eye to the angle subtended by

Vedclass · Accepted Answer

$1 + D/f$

Vedclass · Answer

(B) For a simple microscope,the magnifying power $M$ is defined as the ratio of the angle subtended by the image at the eye to the angle subtended by the object at the near point.When the final image is formed at the near point $D = 25 \ cm$,we use the lens formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$.Here,$v = -D$ and $u = -u$. Substituting these values,we get: $\frac{1}{-D} - \frac{1}{-u} = \frac{1}{f}$.Rearranging the terms: $\frac{1}{u} = \frac{1}{f} + \frac{1}{D}$.Multiplying both sides by $D$,we get: $\frac{D}{u} = \frac{D}{f} + 1$.Since the magnifying power $M = \frac{D}{u}$,we have $M = 1 + \frac{D}{f}$.

Magnifying power of a simple microscope is (when final image is formed at $D = 25 \ cm$ from eye)

Similar Questions

$A$ student measures the thickness of a human hair by looking at it through a microscope of magnification $100$. He makes $20$ observations and finds that the average width of the hair in the field of view of the microscope is $3.5 \; mm$. What is the estimate on the thickness (in $mm$) of hair?

Mention the maximum magnification of a simple microscope.

When can more magnification of a compound microscope be obtained?

$A$ simple microscope is used to see an object first in blue light and then in red light. Due to the change from blue to red light, its magnifying power

Vedclass Test Series

Exam Paper Generator

Online Exam Module