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$A$ galvanometer coil has a resistance of $12\,\Omega$ and the meter shows full-scale deflection for a current of $3\,mA$. To convert it into a voltmeter of range $0-18\,V$,what resistance should be added and how?

$A$ galvanometer has a resistance of $80 \Omega$ and it is shunted with a resistance of $20 \Omega$. If $20 \%$ of the main current flows through the galvanometer, what is the value of the main current (in $\text{ A}$)?

In a circuit for finding the resistance of a galvanometer by the half-deflection method,a $6\,V$ battery and a high resistance of $11\,k\Omega$ are used. The figure of merit of the galvanometer is $60\,\mu A/\text{division}$. In the absence of shunt resistance,the galvanometer produces a deflection of $\theta = 9$ divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of $\theta/2$ is closest to .................. $\Omega$.

The range of a voltmeter of resistance $G \ \Omega$ is $V$ volt. The resistance required to be connected in series with it in order to convert it into a voltmeter of range $nV$ volt, will be

In the experiment to determine the galvanometer resistance by the half-deflection method,the plot of $\frac{1}{\theta}$ vs the resistance $(R)$ of the resistance box is shown in the figure. The figure of merit of the galvanometer is .............. $\times 10^{-1} \text{ A/division}$. [The source has emf $E = 2 \text{ V}$]