Match List-I with List-II. List-I (molec | vedclass

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Question

(A) $IF_7$: Central atom $I$ has $7$ valence electrons, all used in bonding. Lone pairs = $0$ $(IV)$.$ICl_4^-$: Central atom $I$ has $7$ valence elect

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$A-IV, B-III, C-II, D-I$

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(A) $IF_7$: Central atom $I$ has $7$ valence electrons, all used in bonding. Lone pairs = $0$ $(IV)$.$ICl_4^-$: Central atom $I$ has $7$ valence electrons + $1$ (negative charge) = $8$. $4$ electrons used in bonding, leaving $4$ electrons ($2$ lone pairs) $(III)$.$XeF_6$: Central atom $Xe$ has $8$ valence electrons. $6$ used in bonding, leaving $2$ electrons ($1$ lone pair) $(II)$.$XeF_2$: Central atom $Xe$ has $8$ valence electrons. $2$ used in bonding, leaving $6$ electrons ($3$ lone pairs) $(I)$.Correct matching: $A-IV, B-III, C-II, D-I$.

List-$I$ (molecules/ions)	List-$II$ (No. of lone pairs of $e^-$ on central atom)
$A$. $IF_7$	$I$. Three
$B$. $ICl_4^-$	$II$. One
$C$. $XeF_6$	$III$. Two
$D$. $XeF_2$	$IV$. Zero

Match List-$I$ with List-$II$.

List-$I$ (molecules/ions) List-$II$ (No. of lone pairs of $e^-$ on central atom)

$A$. $IF_7$ $I$. Three

$B$. $ICl_4^-$ $II$. One

$C$. $XeF_6$ $III$. Two

$D$. $XeF_2$ $IV$. Zero

Choose the correct answer from the options given below:

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Match List-$I$ with List-$II$. List-$I$ (molecules/ions) List-$II$ (No. of lone pairs of $e^-$ on central atom) $A$. $IF_7$ $I$. Three $B$. $ICl_4^-$ $II$. One $C$. $XeF_6$ $III$. Two $D$. $XeF_2$ $IV$. Zero Choose the correct answer from the options given below: