Match List-I with List-II: List-I (Atomi | vedclass

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(D) To determine the block of an element from its atomic number,we look at the last orbital filled:$1$. Atomic number $37$ is Rubidium $(Rb)$,which be

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$A-IV, B-II, C-I, D-III$

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(D) To determine the block of an element from its atomic number,we look at the last orbital filled:$1$. Atomic number $37$ is Rubidium $(Rb)$,which belongs to the $s$-block (Group $1$). Thus,$A-IV$.$2$. Atomic number $78$ is Platinum $(Pt)$,which is a transition metal belonging to the $d$-block. Thus,$B-II$.$3$. Atomic number $52$ is Tellurium $(Te)$,which belongs to the $p$-block (Group $16$). Thus,$C-I$.$4$. Atomic number $65$ is Terbium $(Tb)$,which is a lanthanoid belonging to the $f$-block. Thus,$D-III$.Therefore,the correct matching is $A-IV, B-II, C-I, D-III$.

List-$I$ (Atomic Number)	List-$II$ (Block of periodic table)
$A$. $37$	$I$. $p$-block
$B$. $78$	$II$. $d$-block
$C$. $52$	$III$. $f$-block
$D$. $65$	$IV$. $s$-block

Match List-$I$ with List-$II$:

List-$I$ (Atomic Number) List-$II$ (Block of periodic table)

$A$. $37$ $I$. $p$-block

$B$. $78$ $II$. $d$-block

$C$. $52$ $III$. $f$-block

$D$. $65$ $IV$. $s$-block

Choose the correct answer from the options given below:

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Match List-$I$ with List-$II$: List-$I$ (Atomic Number) List-$II$ (Block of periodic table) $A$. $37$ $I$. $p$-block $B$. $78$ $II$. $d$-block $C$. $52$ $III$. $f$-block $D$. $65$ $IV$. $s$-block Choose the correct answer from the options given below: